Not sure how to handle this problem. Any help would be appreciated.
ln^2(X) + ln(X)^3 + 2 = 0
In the first term the exponent is with the natural log. In the second term the exponent is with the X value.
I know it can be written like this:
ln^2(X) + 3ln(X) + 2 = 0
But I don't know how to deal with the first term.
If it helps, the answers are supposed to bex=e^-1orx=e^-2.
ln^2(X) + ln(X)^3 + 2 = 0
In the first term the exponent is with the natural log. In the second term the exponent is with the X value.
I know it can be written like this:
ln^2(X) + 3ln(X) + 2 = 0
But I don't know how to deal with the first term.
If it helps, the answers are supposed to bex=e^-1orx=e^-2.